The derivative of tanx with respect to sinx is equal to sec^{3}x, and it is denoted by d/dsinx (tanx). That is,

$\dfrac{d}{d \sin x}(\tan x)=\sec^3 x$.

## Derivative of tanx w.r.t sinx

**Question:** Find the derivative of tanx w.r.t sinx, that is,

Find $\dfrac{d}{d \sin x}(\tan x)$.

**Answer:**

Let us put

u=tanx and v=sinx.

Here we need to find $\dfrac{du}{dv}$. Differentiating u and v with respect to x, we get that

$\dfrac{du}{dx}=\sec^2 x$ and $\dfrac{dv}{dx}=\cos x$

Now, we have that

$\dfrac{du}{dv} = \dfrac{\frac{du}{dx}}{\frac{dv}{dx}}$

⇒ $\dfrac{du}{dv}$ = $\dfrac{\sec^2 x}{\cos x}$

⇒ $\dfrac{du}{dv}$ = sec^{2}x ⋅ secx, as we know that secx =1/cosx.

⇒ $\dfrac{du}{dv}$ = sec^{3}x.

So the derivative of tanx with respect to sinx is equal to sec^{3}x.

**More Derivatives:** Derivative of natural log of x

Derivative of sinx with respect to cosx

Derivative of e^{sinx} | Derivative of e^{cosx}

## FAQs

### Q1: What is the derivative of tanx with respect to sinx?

**Answer:** The derivative of tanx with respect to sinx is equal to sec^{3}x.

### Q2: What is d/dsinx (tanx)?

**Answer:** d/dsinx (tanx) = sec^{3}x.