The derivative of sinx with respect to cosx is denoted by d/dcosx (sinx), and it is equal to -cotx. That is,

$\dfrac{d}{d \cos x}(\sin x)=-\cot x$.

Let us now learn how to differentiate sin x with respect to cos x.

## Derivative of sinx w.r.t cosx

**Question:** Find the derivative of sinx w.r.t cosx, that is,

Find $\dfrac{d}{d \cos x}(\sin x)$.

**Answer:**

Let u=sinx and v=cosx.

So we need to find $\dfrac{du}{dv}$.

Differentiating u and v with respect to x, we get that

$\dfrac{du}{dx}=\cos x$ and $\dfrac{dv}{dx}=-\sin x$

Therefore,

$\dfrac{du}{dv} = \dfrac{\frac{du}{dx}}{\frac{dv}{dx}}$

⇒ $\dfrac{du}{dv}$ = $\dfrac{\cos x}{-\sin x}$

⇒ $\dfrac{du}{dv}$ = – cotx.

So the derivative of sinx with respect to cosx is equal to -cotx.

**More Derivatives:** Derivative of natural log of x

Derivative of e^{sinx} | Derivative of e^{cosx}

## FAQs

### Q1: What is the derivative of sinx with respect to cosx?

**Answer:** The derivative of sinx with respect to cosx is equal to -cotx.

### Q2: What is d/dcosx (sinx)?

**Answer:** d/dcosx (sinx) = -cotx.