The limit of 1/x^2 as x approaches infinity is equal to 0. As this limit is denoted by lim_{x→∞} 1/x^{2}, so the formula of the limit of 1/x^{2} is given as follows:

lim_{x→∞} 1/x^{2} = 0

## What is the Limit of 1/x^{2} when x**→**∞

**Answer:** lim_{x→∞} $\dfrac{1}{x^2}$ = 0.

**Explanation:**

As lim_{x→∞} f(x)/g(x) is written as $\dfrac{\lim\limits_{x \to \infty}f(x)}{\lim\limits_{x \to \infty} g(x)}$, the given limit will be equal to

lim_{x→∞} 1/x^{2}

= $\dfrac{\lim\limits_{x \to \infty} 1}{\lim\limits_{x \to \infty} x^2}$

= $\dfrac{1}{\lim\limits_{x \to \infty} x^2}$

= $\dfrac{1}{\infty}$

= 0.

So the limit of 1/x^{2} is equal to 0 when x tends to infinity.

More Limits:

Limit of x^{2}sin(1/x) when x→0

## Question-Answer

**Question:** Find the limit of 1/x^{n} when x**→**∞ (for n>1), that is find the limit

lim_{x→∞} 1/x^{n}

**Answer:**

We will proceed as above. So the given limit can be written as lim _{x→∞} 1/x^{n}= $\dfrac{\lim\limits_{x \to \infty} 1}{\lim\limits_{x \to \infty} x^n}$ = $\dfrac{1}{\lim\limits_{x \to \infty} x^n}$ = 1/∞ = 0. Hence, the limit of 1 divided by x ^{n} (for n >1) is equal to 0 when x approaches infinity. |

## FAQs

### Q1: What is lim_{x→0} 1/x^{2}?

Answer: The limit of 1/x^{2} is 0 when x tends to ∞, that is, lim_{x→∞} 1/x^{2} =0.