Integral of square root tanx | Find ∫√tanx dx
The integral of root tanx is equal to ∫√tanx dx = $\dfrac{1}{\sqrt{2}}$ tan-1 ($\dfrac{\tan x-1}{\sqrt{2\tan x}}$) + $\dfrac{1}{2\sqrt{2}}$ log $|\dfrac{\tan x+1-\sqrt{2\tan x}}{\tan x+1+\sqrt{2\tan x}}|$ +C where C denotes an integral constant. In this post, we will learn how to find the integral of square root of tanx. Integration of √tanx Question: Find ∫√tanx dx. Solution: … Read more