The sin cube x formula is given as follows: sin^{3}x = (3sinx -sin3x)/4, that is, sin^3x formula is equal to (3sinx – sin3x) divided by 4. Here we establish the formula of sine cube x and give a proof.

## What is sin cube x formula

**Answer:** sin^{3}x = (3sinx -sin3x)/4

*Proof:*

To establish the formula of sin^3x, we will use sin3x formula which is provided below:

sin3x = 3sinx – 4sin^{3}x.

Adding -3sinx to both sides, we get that

– 3sinx + sin3x = – 3sinx + 3sinx – 4sin^{3}x

⇒ – 3sinx + sin3x = – 4sin^{3}x

⇒ 3sinx – sin3x = 4sin^{3}x (changing the signs)

Dividing both sides, we obtain that

(3sinx – sin3x)/4 = sin^{3}x.

So the sin^{3}x formula is given by sin^{3}x = (3sinx – sin3x)/4 and this is proved by using the formula of sin3x.

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## FAQs

**Q1: What is the sin^3x formula?**

**Answer:** sin^{3}x = (3sinx – sin3x)/4 is the formula of sin^3x.

**Q2: What is the sin^3θ formula?**

**Answer:** The sin cube theta formula says that sin^{3}θ = (3sinθ -sin3θ)/4.

**Q3: What is the formula of sin 3theta?**

**Answer:** Sin 3theta formula is equal to 3 sin theta – 4 sin 3theta.