The integration of x^{n} is given as follows: ∫x^{n}dx = x^{n+1}/(n+1) + C where C is an integration constant. In this post, we will learn how to find the integral of x to the power n.

## Integration of x^{n} Formula

The integration formula of x^{n} (n-th power x) is given below:

∫x^{n}dx = x^{n+1}/(n+1) + C

where C is an integral constant. This rule is called the power rule of integration.

## Integration of x^{n} Proof

We know that the derivative of x^{k} is equal to kx^{k-1}. Putting k=n+1 we get that

$\dfrac{d}{dx}(x^{n+1})=(n+1)x^n$ **…(I)**

As the integration (anti-derivative) is the inverse process of derivatives, integrating both sides of **(I)** we get that

$x^{n+1}=\int (n+1)x^n \ dx +C’$ where C is an integral constant.

⇒ $x^{n+1}=(n+1) \int x^n \ dx +C’$ by the multiplied by constant rule of integration.

⇒ $\dfrac{x^{n+1}}{n+1}= \int x^n \ dx +\dfrac{C’}{n+1}$

⇒ $\int x^n \ dx=\dfrac{x^{n+1}}{n+1}+C$ where $C=-\dfrac{C’}{n+1}$

So the integration of x to the power n is equal to x^{n+1}/(n+1)+C where C is an integration constant.

**Few Examples,**

- The integration of x is equal to $\int x \ dx = \dfrac{x^2}{2}+C$
- The integration of x
^{2}(x square) is equal to $\int x^2 \ dx = \dfrac{x^3}{3}+C$ - The integration of x
^{3}(x cube) is equal to $\int x^3 \ dx = \dfrac{x^4}{4}+C$ - But, using the above power rule of integration, we cannot find the integration of 1/x. This is because x
^{-1+1}/(-1+1), so we are getting 0 in the denominator. Hence, it does not exist. The integration of 1/x is equal to $\int \dfrac{1}{x} dx = \ln x+C$ where ln denotes the natural logarithm (that is, logarithm with base e).

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## FAQs

**Q1: What is the integration of x ^{n}?**

**Answer:** The integration of x^{n} is equal to ∫x^{n}dx = x^{n+1}/(n+1) + C.