The integration of root x + 1/root x is equal to 2/3 x^{3/2}+2*√*x+C where C is an integral constant. In this post, we will learn how to integrate √x+1/√x.

## Integral of √x+1/√x

**Question:** Find the integral $\int (\sqrt{x}+\dfrac{1}{\sqrt{x}})\ dx$

*Answer:*

$\int (\sqrt{x}+\dfrac{1}{\sqrt{x}})\ dx$ = $\int \sqrt{x}\ dx$ + $\int \dfrac{1}{\sqrt{x}}\ dx$ by the sum rule of integration.

= ∫ x^{1/2} dx + $\int \dfrac{1}{x^{1/2}}\ dx$

= ∫ x^{1/2} dx + ∫ x^{-1/2} dx

= $\dfrac{x^{\frac{1}{2}+1}}{\frac{1}{2}+1}$ + $\dfrac{x^{-\frac{1}{2}+1}}{-\frac{1}{2}+1}$ using the power rule of integration: $\int x^n dx =\dfrac{x^{n+1}}{n+1}$

= $\dfrac{x^{3/2}}{3/2}$ + $\dfrac{x^{1/2}}{1/2}$ + C where C is an integration constant.

= $\dfrac{2}{3} x^{3/2}$ $+2 \sqrt{x}$ + C

= $\dfrac{2}{3} x\sqrt{x}$ $+2 \sqrt{x}$ + C as we have $x^{3/2}=x\sqrt{x}$ by the power rule of indices.

So the integral of √x+1/√x is equal to $\dfrac{2}{3} x\sqrt{x}$ $+2 \sqrt{x}$ + C where C is an integration constant.

**ALSO READ:**

## FAQ

**Q1: What is the integration of √x+1/√x?**

**Answer:** The integration of √x+1/√x is equal to ∫(√x+1/√x)dx = 2/3 x√x + 2√x + C.