Derivative of 2^x by First Principle

The derivative of 2x is equal to 2xln2 where ln 2 is the natural logarithm of 2, that is, ln 2 = loge2. In this post, we will find the derivative of 2x by the first principle of derivatives. Derivative of 2x from First Principle We know that the derivative of a function f(x) by … Read more

Derivative of xe^x by First Principle, Product Rule

The derivative of xex is equal to (1+x)ex. In this post, we will find the derivative of xex by the first principle and by the product rule of derivatives. The first principle of derivatives says that the derivative of a function f(x) is given by the following limit formula:   $\dfrac{d}{dx}(f(x))$ $=\lim\limits_{h \to 0} \dfrac{f(x+h)-f(x)}{h}$ … Read more

What is the Integration of 1/(1+x^2) | Integral of 1/(1+x^2)

The integration of  1/(1+x2) is equal to tan2 x. In this post, we will see how to integrate 1/(1+x^2). Integration of $\dfrac{1}{1+x^2}$ Question: What is the integration of $\dfrac{1}{1+x^2}$? That is, Find $\int \dfrac{1}{1+x^2} dx$ Answer: The integration of $\dfrac{1}{1+x^2}$ is $\tan^2 x$. Explanation: Let us substitute $x=\tan t$ $\cdots (\star)$ Differentiating with respect to … Read more

Maclaurin series of sinx | Taylor series of sinx

The Maclaurin series expansion of sinx or the Taylor series expansion of sinx at x=0 is given as follows: $\sin x= \sum_{n=0}^\infty \dfrac{(-1)^n}{(2n+1)!}x^{2n+1}$ $=x-\dfrac{x^3}{3!}+\dfrac{x^5}{5!}-\cdots$ Taylor Series Expansion of Sinx at x=0 We know that the Maclaurin series expansion of $\sin x$ or the Taylor series of a function $f(x)$ at $x=0$ is given by the … Read more

Find Integral of e^3x | e^3x Integration

The integration of e3x is e3x/3. In this post, we will learn how to find the integral of e to the 3x. Let us recall the formula of the integral of emx: $\int e^{mx} dx=\dfrac{e^{mx}}{m}+C$ where C is an integral constant. Thus, the integral of e3x will be equal to $\int e^{3x} dx=\dfrac{e^{3x}}{3}+C$. What is the … Read more

Find the Derivative of sin5x [by First Principle]

The derivative of sin5x is equal to 5cos5x.  In this post, we will find the derivative of sin5x by the first principle, that is, by the limit definition of derivatives. By the first principle of derivatives, we know that the derivative of a function f(x) is given by the following limit: $\dfrac{d}{dx}(f(x))$$=\lim\limits_{h\to 0} \dfrac{f(x+h)-f(x)}{h}$ …(I) Derivative … Read more

Derivative of cos(e^x) by Chain Rule

The derivative of cos(ex) is equal to -ex sin(ex). In this post, we will learn how to find the derivative of cos(ex) by the chain rule of derivatives. Derivative of cos(ex) Question: Find the derivative of cos(ex). Answer: The derivative of cos(ex) is equal to -exsin(ex). Explanation: Note that f(x)=cos(ex) is a composite function. The … Read more