# [Solved] What is the Derivative of 2^x [2 to the x]?

The derivative of 2x is equal to 2x ln2. Here, ln denotes the natural logarithm (logarithm with base e). In this post, we will find the derivative of 2 to the power x.

## Derivative of 2x Formula

As we know that the derivative of ax is axln a, the formula for the derivative of 2x will be as follows:

$\dfrac{d}{dx}(2^x)=2^x \ln 2$

or

$(2^x)’=2^x \ln 2$.

Here, the prime $’$ denotes the first-order derivative.

## What is the Derivative of 2x?

Answer: The derivative of 2x is 2xln 2.

Explanation:

We will use the logarithmic differentiation to find the derivative of 2 raised to x. To do so, let us put

z=2x

Taking natural logarithms $\ln$ of both sides, we obtain that

$\ln z=\ln 2^x$

$\Rightarrow \ln z=x\ln 2$ as we know that ln ab = b ln a

Differentiating both sides with respect to x, we get that

$\dfrac{1}{z} \dfrac{dz}{dx}=\ln 2$

$\Rightarrow \dfrac{dz}{dx}=z\ln 2$

$\Rightarrow \dfrac{dz}{dx}=2^x\ln 2$ as z=2x.

Thus, the derivative of 2^x is 2x ln2.

Derivative of e2

Derivative of Pi

Derivative of sin4x

Derivative of sin5x

Derivative of 2x at x=0

From the above, we obtain the derivative of 2x which is equal to 2x ln 2. So the derivative of 2 to the power x at x=0 will be equal to

$d/dx[2^x]{x=0}$ $=[2^x \ln 2]{x=0}$

= 20 ln 2

= ln 2 as we know that x0=1 for any non-zeero x.

Thus, the derivative of  2x at x=0 is ln 2.