The integral of 1/2x (1 by 2x) is equal to 1/2 ln|x|+C where C denotes an integration constant. Here we learn how to integrate 1/2x. The integration of 1/2x formula is given by
$\int \dfrac{1}{2x} dx=\dfrac{1}{2}\ln |x|+C$.
Integration of 1/2x
Answer: The integration of 1/2x is 1/2 ln|x|+C.
Explanation:
We need to find the integral
$\int \dfrac{1}{2x} \ dx$.
Let us put ln x = t.
Differentiating, $\dfrac{dx}{x}$ = dt.
Thus, $\int \dfrac{1}{2x} \ dx$
= $\dfrac{1}{2} \int \dfrac{dx}{x}$ as 1/2 is a constant.
= $\dfrac{1}{2} \int dt$
= $\dfrac{1}{2} t +C$
= $\dfrac{1}{2} \ln |x| +C$ as ln is defined for positive values only.
That is, $\int \dfrac{1}{2x} \ dx$ = $\dfrac{1}{2} \ln |x| +C$.
So the integration of 1/2x is equal to 1/2 ln|x|+C where C denotes an arbitrary integral constant.
More Integrals:
Integral of ln(x) | Integral of ln2x
Integration of square root of cotx
FAQs
Q1: What is the integral of 1/2x?
Answer: The integral of 1/2x is 1/2 ln|x|+C, that is, ∫1/2x dx = 1/2 ln|x|+C.