The derivative of lnx^2 is equal to 2/x. The natural logarithm of x^{2} is denoted by ln(x^{2}), and its derivative formula is given by

$\dfrac{d}{dx}(\ln x^2)=\dfrac{2}{x}.$

That is, the differentiation of ln(x^{2}) is 2/x.

## Derivative of ln(x^{2}) by Chain Rule

Answer: The derivative of ln(x^{2}) is 2/x. |

**Explanation:**

To find the derivative of ln(x^{2}) by the chain rule, let us put

z = x^{2}.

So $\dfrac{dz}{dx}$ = 2x.

Now,

$\dfrac{d}{dx}(\ln x^2)$ = $\dfrac{d}{dz}(\ln z) \times \dfrac{dz}{dx}$

= $\dfrac{1}{z} \times 2x$

= $\dfrac{2x}{z}$

= $\dfrac{2x}{x^2}$ as z=x^{2}.

= $\dfrac{2}{x}$.

So the derivative of ln(x^{2}) is equal to 2/x, and this is obtained by the chain rule of differentiation.

**More Derivatives:**

## FAQs

### Q1: What is the derivative of ln(x^{2})?

Answer: The derivative of ln(x^{2}) with respect to x is equal to 2/x.

### Q2: If y=ln(x^{2}), then find dy/dx.

Answer: If y= ln(x^{2}), then dy/dx =2/x.