What is the Integration of tan^2x | Integral of tan^2 x

The integration of tan^2x is equal to ∫tan2x dx = tan (x)-x. In this post, we will learn how to find the integral of tan square x. We will use the following two formulas:

  1. ∫sec2x dx =tan x+C
  2. ∫dx = x+C
Integration of tan^2x

Integration of tan2x

Question: What is the integration of tan2 x? That is, find ∫tan2 x dx.

Answer: ∫tan2x dx = tan(x) -x +C.

Explanation:

To find the integration of tan2x, we will proceed as follows. At first, we will use the formula given below.

sec2 x =1+tan2 x

⇒ tan2 x = sec2 x -1

Therefore, we have that ∫tan2x dx = ∫(sec2 x-1) dx

= ∫sec2 x dx – ∫dx

= tan x – x +C by the above formulas.

So the integration of tan2 x is equal to tan(x)-x+C where C is an integration constant.

Definite Integral of tan2x

Question: Find the definite integral $\int_0^{\frac{\pi}{4}} \tan^2 x dx$

Answer:

From the above, we know that the integration of tan square x is ∫tan2x dx = tan x – x +C. Therefore, the given definite integral will be equal to

$\int_0^{\frac{\pi}{4}} \tan^2 x dx$

= $[\tan x -x]_0^{\frac{\pi}{4}}$

= $(\tan \frac{\pi}{4}-  \frac{\pi}{4})$ $-(\tan 0 -0)$

= $(1-  \frac{\pi}{4})-(0 -0)$ as the value of $\tan \frac{\pi}{4}$ is $1$ and the value of tan0 is 0.

= $1-  \frac{\pi}{4}$.

Thus, the integral of tan2x from 0 to π/4 is equal to 1-π/4.

Also Read: 

Integration of log(sinx) from 0 to pi/2

Integration of e3x

Derivative & Integration of 1/root(x)

Integration of 1/(1+x2)

FAQs

Q1: What is the integration formula of tan2x?

Answer: The integration formula of tan square x is as follows: ∫tan2x dx = tan(x) -x +C.

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