The value of the expression 1-sin^2(x) is equal to cos^2(x). In this post, we will find the formula of 1-sin^2x.

## 1-sin^{2}x Formula

To simplify the expression $1-\sin^2 x$, we will follow the below steps:

**Step 1:** Let us apply the following Pythagorean trigonometric identity:

$1=\sin^2 x +\cos^2 x$ $\cdots (\star)$

**Step 2:** Now, we substitute the value of $1$ in the expression $1-\sin^2 x$. By doing so we get that

$1-\sin^2 x= (\sin^2 x +\cos^2 x)-\sin^2 x$

$=\sin^2 x +\cos^2 x-\sin^2x$

$=\cos^2 x$ Conclusion:

Thus, the formula of $1-\sin^2 x$ is equal to $\cos^2 x$.

**Note** that we also have that $1-\sin^2 \theta=\cos^2 \theta$ and this is obtained in a similar way as above.

**Also Read:**

**sinx=0, cosx=0, tanx=0 General Solution**

**Values of sin 15, cos 15, tan 15**

**Values of sin 75, cos 75, tan 75**

## Question-Answer on 1-sin2x Formula

**Question 1:** Find the value of $1-\sin^2 60^\circ$

*Answer:*

From the above, we get the value of $1-\sin^2 x$ which is equal to $\cos^2 x$. In this formula, we put $x=60^\circ$. So we get that

$1-\sin^2 60^\circ$

$=\cos^2 60^\circ$

$=(\dfrac{1}{2})^2$

$=1/4$ as we know that $\cos 60^\circ =1/2$.

Thus, the value of $1-\sin^2 60^\circ$ is equal to $1/4$.

## FAQs

**Q1: What is the formula of 1-sin ^{2}x?**

Answer: The formula is 1-sin^{2}x=cos^{2}x**.**