Derivative of x root(x) by First Principle

The derivative of x root x is 3 root(x)/2. In this post, we will find the derivative of x root(x) from first principle. This principle says that the derivative of f(x) is

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$\dfrac{d}{dx}(f(x))$ $=\lim\limits_{h \to 0}\dfrac{f(x+h)-f(x)}{h}$ $\quad \cdots (I)$

Derivative of x root(x) by first principle

Derivative of x root x by First Principle

Let $f(x)=x\sqrt{x}$ in the above formula (I). So the derivative of x root x using first principle is equal to

$\dfrac{d}{dx}(x \sqrt{x})$ $=\lim\limits_{h \to 0}\dfrac{(x+h)\sqrt{x+h}-x\sqrt{x}}{h}$

We will multiply the numerator with its conjugate.

$=\lim\limits_{h \to 0}[\dfrac{(x+h)\sqrt{x+h}-x\sqrt{x}}{h}$ $\times \dfrac{(x+h)\sqrt{x+h}+x\sqrt{x}}{(x+h)\sqrt{x+h}+x\sqrt{x}}]$

Apply the formula of $(a-b)(a+b)$ $=a^2-b^2$ in the numerator. By doing that we get

$=\lim\limits_{h \to 0}\dfrac{[(x+h)\sqrt{x+h}]^2-(x\sqrt{x})^2}{h((x+h)\sqrt{x+h}+x\sqrt{x})}$

$=\lim\limits_{h \to 0}\dfrac{(x+h)^3-x^3}{h((x+h)\sqrt{x+h}+x\sqrt{x})}$

Now, we will use the formula of $a^3-b^3$ $=(a-b)(a^2+ab+b^2)$ in the numerator. So the above limit

$=\lim\limits_{h \to 0}\dfrac{h(3x^2+3xh+h^2)}{h((x+h)\sqrt{x+h}+x\sqrt{x})}$

$=\lim\limits_{h \to 0}\dfrac{3x^2+3xh+h^2}{(x+h)\sqrt{x+h}+x\sqrt{x}}$

$=\dfrac{3x^2+3x \cdot 0+0^2}{(x+0)\sqrt{x+0}+x\sqrt{x}}$ $=\dfrac{3x^2}{2x\sqrt{x}}$

$=\dfrac{3\sqrt{x}}{2}$

Thus, the derivative of x root(x) is 3 root(x)/2 obtained by the first principle of derivatives.

Also Read: Derivative of root(x)+1/root(x)

Derivative of root(1+x) from first principle

Derivative of root sin x from first principle

Derivative of root cos x from first principle

Note: The derivative of r root(x) can be computed by the power rule of derivatives easily. See that

$x\sqrt{x}=x^{1+1/2}$ $=x^{3/2}$.

$\therefore \dfrac{d}{dx}(x\sqrt{x})$ $=\dfrac{d}{dx}(x^{\frac{3}{2}})$

$=3/2 x^{3/2-1}$ as we know that $\dfrac{d}{dx}(x^n)=nx^{n-1}$. Here $n=3/2$.

$=3/2 x^{1/2}$

$=\dfrac{3\sqrt{x}}{2}$

Also Read:

Derivative of e3x

Derivative of e2x from first principle

Derivative of log(sin x) from first principle

Derivative of log(3x) from first principle

Derivative of log(cos x) from first principle

FAQs

Q1: What is the derivative of x√x?

Answer: The derivative of x√x is equal to 3√x/2.

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